how to calculate 1/i^27?
imaginary number whats the answer for 1/i^27 ?
A-Best: first u try to express i in nearest multiple of 4 + some other no
(sine i^4 is 1)
thus if u hav i^27 the multiple of 4 is 24
thus write i^27 as i^24 * i^3
i^24 = (i^4)^6 =1
also remember the following
i^2 = -1
i^3 = -i
1/i = -i
now
1/i^27 = 1/i^3 =1 / -i = i
A: sorry usp ur whole answer is rite except the last part......1/(-i) is just 1/(-i) and not "i"....btw the rest of the ans is rite
A: Since i^4n = 1 for all n, you have
1 / i^27 = i / i^28 = i.
Simple as that.
A: The way to do it is:
i^1=i
i^2=-1
i^3=-i
i^4 =1 And now the cycle repeats
So divide the exponent of i into 4 and take the remainder
27 = 6*4+3 so i^27 = i^3 =-i and 1/(-i) = i To see this multiply numerator and denominator by i
